Base | Representation |
---|---|
bin | 1001000111000110110110… |
… | …01101000101110010110001 |
3 | 2121221100212211102110122202 |
4 | 10203203123031011302301 |
5 | 10111230002202013244 |
6 | 110340045452312545 |
7 | 4135340005343141 |
oct | 443433315056261 |
9 | 77840784373582 |
10 | 20035405110449 |
11 | 6424a709545a3 |
12 | 22b6bb4772755 |
13 | b2443b418131 |
14 | 4d3a0c49c921 |
15 | 24b27828904e |
hex | 1238db345cb1 |
20035405110449 has 2 divisors, whose sum is σ = 20035405110450. Its totient is φ = 20035405110448.
The previous prime is 20035405110419. The next prime is 20035405110463. The reversal of 20035405110449 is 94401150453002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13020153639025 + 7015251471424 = 3608345^2 + 2648632^2 .
It is a cyclic number.
It is not a de Polignac number, because 20035405110449 - 244 = 2443219066033 is a prime.
It is not a weakly prime, because it can be changed into another prime (20035405110419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10017702555224 + 10017702555225.
It is an arithmetic number, because the mean of its divisors is an integer number (10017702555225).
Almost surely, 220035405110449 is an apocalyptic number.
It is an amenable number.
20035405110449 is a deficient number, since it is larger than the sum of its proper divisors (1).
20035405110449 is an equidigital number, since it uses as much as digits as its factorization.
20035405110449 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 38.
The spelling of 20035405110449 in words is "twenty trillion, thirty-five billion, four hundred five million, one hundred ten thousand, four hundred forty-nine".
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