Base | Representation |
---|---|
bin | 10010101010001101… |
… | …000010011000110101 |
3 | 1220201022011110111222 |
4 | 102222031002120311 |
5 | 312013031213212 |
6 | 13112032240125 |
7 | 1306332130265 |
oct | 225215023065 |
9 | 56638143458 |
10 | 20035413557 |
11 | 8551517825 |
12 | 3a719a0045 |
13 | 1b73b269c3 |
14 | d80ca37a5 |
15 | 7c3e13c72 |
hex | 4aa342635 |
20035413557 has 2 divisors, whose sum is σ = 20035413558. Its totient is φ = 20035413556.
The previous prime is 20035413473. The next prime is 20035413571. The reversal of 20035413557 is 75531453002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10314636721 + 9720776836 = 101561^2 + 98594^2 .
It is a cyclic number.
It is not a de Polignac number, because 20035413557 - 210 = 20035412533 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20035413577) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10017706778 + 10017706779.
It is an arithmetic number, because the mean of its divisors is an integer number (10017706779).
Almost surely, 220035413557 is an apocalyptic number.
It is an amenable number.
20035413557 is a deficient number, since it is larger than the sum of its proper divisors (1).
20035413557 is an equidigital number, since it uses as much as digits as its factorization.
20035413557 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 63000, while the sum is 35.
Adding to 20035413557 its reverse (75531453002), we get a palindrome (95566866559).
The spelling of 20035413557 in words is "twenty billion, thirty-five million, four hundred thirteen thousand, five hundred fifty-seven".
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