Base | Representation |
---|---|
bin | 11101001001111100100… |
… | …110000011111010010001 |
3 | 21002112111111121012200021 |
4 | 131021330212003322101 |
5 | 230311230022042314 |
6 | 4132225501023441 |
7 | 264515500314124 |
oct | 35117446037221 |
9 | 7075444535607 |
10 | 2003545112209 |
11 | 702775a90093 |
12 | 284373254b81 |
13 | 116c19b673c4 |
14 | 6cd876323bb |
15 | 371b434b324 |
hex | 1d27c983e91 |
2003545112209 has 2 divisors, whose sum is σ = 2003545112210. Its totient is φ = 2003545112208.
The previous prime is 2003545112201. The next prime is 2003545112281. The reversal of 2003545112209 is 9022115453002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2000979993600 + 2565118609 = 1414560^2 + 50647^2 .
It is a cyclic number.
It is not a de Polignac number, because 2003545112209 - 23 = 2003545112201 is a prime.
It is not a weakly prime, because it can be changed into another prime (2003545112201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001772556104 + 1001772556105.
It is an arithmetic number, because the mean of its divisors is an integer number (1001772556105).
Almost surely, 22003545112209 is an apocalyptic number.
It is an amenable number.
2003545112209 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003545112209 is an equidigital number, since it uses as much as digits as its factorization.
2003545112209 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 34.
The spelling of 2003545112209 in words is "two trillion, three billion, five hundred forty-five million, one hundred twelve thousand, two hundred nine".
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