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20040222113477 is a prime number
BaseRepresentation
bin1001000111001111110100…
…10100011111111011000101
32121221211022112110120120022
410203213322110133323011
510111314333330112402
6110342203445344525
74135600246240556
oct443477224377305
977854275416508
1020040222113477
116427012a32235
1222b7b19a08145
13b24a28393997
144d3d4812632d
1524b45b0e42a2
hex1239fa51fec5

20040222113477 has 2 divisors, whose sum is σ = 20040222113478. Its totient is φ = 20040222113476.

The previous prime is 20040222113399. The next prime is 20040222113489. The reversal of 20040222113477 is 77431122204002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12450164053441 + 7590058060036 = 3528479^2 + 2755006^2 .

It is a cyclic number.

It is not a de Polignac number, because 20040222113477 - 232 = 20035927146181 is a prime.

It is a super-2 number, since 2×200402221134772 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20040222113677) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10020111056738 + 10020111056739.

It is an arithmetic number, because the mean of its divisors is an integer number (10020111056739).

Almost surely, 220040222113477 is an apocalyptic number.

It is an amenable number.

20040222113477 is a deficient number, since it is larger than the sum of its proper divisors (1).

20040222113477 is an equidigital number, since it uses as much as digits as its factorization.

20040222113477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 37632, while the sum is 35.

Adding to 20040222113477 its reverse (77431122204002), we get a palindrome (97471344317479).

The spelling of 20040222113477 in words is "twenty trillion, forty billion, two hundred twenty-two million, one hundred thirteen thousand, four hundred seventy-seven".