Base | Representation |
---|---|
bin | 1001000111010001100001… |
… | …00011100001011001010111 |
3 | 2121221220122221121200111100 |
4 | 10203220300203201121113 |
5 | 10111323214244140320 |
6 | 110342434032041143 |
7 | 4135631635313265 |
oct | 443506043413127 |
9 | 77856587550440 |
10 | 20041132021335 |
11 | 642743a6114a7 |
12 | 22b81326931b3 |
13 | b24b41a48cb9 |
14 | 4d3dd2d01435 |
15 | 24b4b0e2b790 |
hex | 123a308e1657 |
20041132021335 has 24 divisors (see below), whose sum is σ = 36248308353504. Its totient is φ = 10223881842240.
The previous prime is 20041132021297. The next prime is 20041132021343. The reversal of 20041132021335 is 53312023114002.
20041132021335 is a `hidden beast` number, since 2 + 0 + 0 + 4 + 1 + 1 + 320 + 2 + 1 + 335 = 666.
It is not a de Polignac number, because 20041132021335 - 26 = 20041132021271 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20041132021299 and 20041132021308.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 9681705256 + ... + 9681707325.
It is an arithmetic number, because the mean of its divisors is an integer number (1510346181396).
Almost surely, 220041132021335 is an apocalyptic number.
20041132021335 is a deficient number, since it is larger than the sum of its proper divisors (16207176332169).
20041132021335 is a wasteful number, since it uses less digits than its factorization.
20041132021335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19363412615 (or 19363412612 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 27.
Adding to 20041132021335 its reverse (53312023114002), we get a palindrome (73353155135337).
The spelling of 20041132021335 in words is "twenty trillion, forty-one billion, one hundred thirty-two million, twenty-one thousand, three hundred thirty-five".
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