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2004143161351 is a prime number
BaseRepresentation
bin11101001010100000001…
…111011100000000000111
321002121001011221020212111
4131022200033130000013
5230313441122130401
64132405103201451
7264536351536462
oct35124017340007
97077034836774
102004143161351
11702a52626281
122844bb5a6287
13116cb3a2c036
146d002c2c2d9
15371ebad0e51
hex1d2a03dc007

2004143161351 has 2 divisors, whose sum is σ = 2004143161352. Its totient is φ = 2004143161350.

The previous prime is 2004143161337. The next prime is 2004143161379. The reversal of 2004143161351 is 1531613414002.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2004143161351 - 211 = 2004143159303 is a prime.

It is a super-2 number, since 2×20041431613512 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2004143161051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1002071580675 + 1002071580676.

It is an arithmetic number, because the mean of its divisors is an integer number (1002071580676).

Almost surely, 22004143161351 is an apocalyptic number.

2004143161351 is a deficient number, since it is larger than the sum of its proper divisors (1).

2004143161351 is an equidigital number, since it uses as much as digits as its factorization.

2004143161351 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 2004143161351 its reverse (1531613414002), we get a palindrome (3535756575353).

The spelling of 2004143161351 in words is "two trillion, four billion, one hundred forty-three million, one hundred sixty-one thousand, three hundred fifty-one".