Base | Representation |
---|---|
bin | 1001000111010011101110… |
… | …10111110011100101000111 |
3 | 2121222000201202020222111201 |
4 | 10203221313113303211013 |
5 | 10111333132423214143 |
6 | 110343151553243331 |
7 | 4136003243144101 |
oct | 443516727634507 |
9 | 77860652228451 |
10 | 20042320132423 |
11 | 642799a237996 |
12 | 22b8404563547 |
13 | b24ca0c39c04 |
14 | 4d40a6a18571 |
15 | 24b5303b964d |
hex | 123a775f3947 |
20042320132423 has 2 divisors, whose sum is σ = 20042320132424. Its totient is φ = 20042320132422.
The previous prime is 20042320132409. The next prime is 20042320132463. The reversal of 20042320132423 is 32423102324002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20042320132423 - 213 = 20042320124231 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20042320132391 and 20042320132400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20042320132463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10021160066211 + 10021160066212.
It is an arithmetic number, because the mean of its divisors is an integer number (10021160066212).
Almost surely, 220042320132423 is an apocalyptic number.
20042320132423 is a deficient number, since it is larger than the sum of its proper divisors (1).
20042320132423 is an equidigital number, since it uses as much as digits as its factorization.
20042320132423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 28.
Adding to 20042320132423 its reverse (32423102324002), we get a palindrome (52465422456425).
The spelling of 20042320132423 in words is "twenty trillion, forty-two billion, three hundred twenty million, one hundred thirty-two thousand, four hundred twenty-three".
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