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200425504000919 is a prime number
BaseRepresentation
bin101101100100100100110010…
…111110000100101110010111
3222021122111020222110220122212
4231210210302332010232113
5202232232413011012134
61550134112212544035
760134156554536401
oct5544446276045627
9867574228426585
10200425504000919
1158952a84a2105a
121a58b97b92201b
1387ab075689912
14376c909087b71
1518287d9a13bce
hexb64932f84b97

200425504000919 has 2 divisors, whose sum is σ = 200425504000920. Its totient is φ = 200425504000918.

The previous prime is 200425504000903. The next prime is 200425504000993. The reversal of 200425504000919 is 919000405524002.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 200425504000919 - 24 = 200425504000903 is a prime.

It is a super-2 number, since 2×2004255040009192 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200425504030919) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100212752000459 + 100212752000460.

It is an arithmetic number, because the mean of its divisors is an integer number (100212752000460).

Almost surely, 2200425504000919 is an apocalyptic number.

200425504000919 is a deficient number, since it is larger than the sum of its proper divisors (1).

200425504000919 is an equidigital number, since it uses as much as digits as its factorization.

200425504000919 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 129600, while the sum is 41.

The spelling of 200425504000919 in words is "two hundred trillion, four hundred twenty-five billion, five hundred four million, nine hundred nineteen", and thus it is an aban number.