Base | Representation |
---|---|
bin | 1001000111010101100101… |
… | …00000000001101010011001 |
3 | 2121222010021212220100012020 |
4 | 10203222302200001222121 |
5 | 10111342200402034001 |
6 | 110343434231405053 |
7 | 4136036650121160 |
oct | 443526240015231 |
9 | 77863255810166 |
10 | 20043312143001 |
11 | 64283591a4144 |
12 | 22b8640823789 |
13 | b250cb60a714 |
14 | 4d415c6863d7 |
15 | 24b58c51d736 |
hex | 123ab2801a99 |
20043312143001 has 128 divisors (see below), whose sum is σ = 32797398306816. Its totient is φ = 10628009533440.
The previous prime is 20043312142981. The next prime is 20043312143011. The reversal of 20043312143001 is 10034121334002.
It is a happy number.
It is not a de Polignac number, because 20043312143001 - 25 = 20043312142969 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (20043312143011) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 5698978095 + ... + 5698981611.
It is an arithmetic number, because the mean of its divisors is an integer number (256229674272).
Almost surely, 220043312143001 is an apocalyptic number.
20043312143001 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
It is an amenable number.
20043312143001 is a deficient number, since it is larger than the sum of its proper divisors (12754086163815).
20043312143001 is a wasteful number, since it uses less digits than its factorization.
20043312143001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4431.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 20043312143001 its reverse (10034121334002), we get a palindrome (30077433477003).
The spelling of 20043312143001 in words is "twenty trillion, forty-three billion, three hundred twelve million, one hundred forty-three thousand, one".
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