Base | Representation |
---|---|
bin | 10010101010101011… |
… | …001111101111100101 |
3 | 1220201212001210101011 |
4 | 102222223033233211 |
5 | 312022043120311 |
6 | 13112514102221 |
7 | 1306456341646 |
oct | 225253175745 |
9 | 56655053334 |
10 | 20043332581 |
11 | 8555a36478 |
12 | 3a7457a971 |
13 | 1b7566a30c |
14 | d81d656cd |
15 | 7c497a321 |
hex | 4aaacfbe5 |
20043332581 has 2 divisors, whose sum is σ = 20043332582. Its totient is φ = 20043332580.
The previous prime is 20043332531. The next prime is 20043332593. The reversal of 20043332581 is 18523334002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13552452225 + 6490880356 = 116415^2 + 80566^2 .
It is a cyclic number.
It is not a de Polignac number, because 20043332581 - 27 = 20043332453 is a prime.
It is a super-2 number, since 2×200433325812 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20043332521) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10021666290 + 10021666291.
It is an arithmetic number, because the mean of its divisors is an integer number (10021666291).
Almost surely, 220043332581 is an apocalyptic number.
It is an amenable number.
20043332581 is a deficient number, since it is larger than the sum of its proper divisors (1).
20043332581 is an equidigital number, since it uses as much as digits as its factorization.
20043332581 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 20043332581 its reverse (18523334002), we get a palindrome (38566666583).
The spelling of 20043332581 in words is "twenty billion, forty-three million, three hundred thirty-two thousand, five hundred eighty-one".
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