Base | Representation |
---|---|
bin | 11101001010101111100… |
… | …111001011101101111111 |
3 | 21002121201011012001211201 |
4 | 131022233213023231333 |
5 | 230320003131404401 |
6 | 4132450434400331 |
7 | 264545632523116 |
oct | 35125747135577 |
9 | 7077634161751 |
10 | 2004401044351 |
11 | 703075153622 |
12 | 284571a300a7 |
13 | 1170252a1824 |
14 | 6d02919ac7d |
15 | 37214570b01 |
hex | 1d2af9cbb7f |
2004401044351 has 2 divisors, whose sum is σ = 2004401044352. Its totient is φ = 2004401044350.
The previous prime is 2004401044267. The next prime is 2004401044439. The reversal of 2004401044351 is 1534401044002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2004401044351 - 233 = 1995811109759 is a prime.
It is a super-2 number, since 2×20044010443512 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2004401044951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1002200522175 + 1002200522176.
It is an arithmetic number, because the mean of its divisors is an integer number (1002200522176).
Almost surely, 22004401044351 is an apocalyptic number.
2004401044351 is a deficient number, since it is larger than the sum of its proper divisors (1).
2004401044351 is an equidigital number, since it uses as much as digits as its factorization.
2004401044351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 28.
Adding to 2004401044351 its reverse (1534401044002), we get a palindrome (3538802088353).
The spelling of 2004401044351 in words is "two trillion, four billion, four hundred one million, forty-four thousand, three hundred fifty-one".
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