Base | Representation |
---|---|
bin | 10010101010101110… |
… | …010010110001011111 |
3 | 1220201220120101011220 |
4 | 102222232102301133 |
5 | 312022244201143 |
6 | 13112543144423 |
7 | 1306466206641 |
oct | 225256226137 |
9 | 56656511156 |
10 | 20044131423 |
11 | 8556431678 |
12 | 3a748a5113 |
13 | 1b75889ac4 |
14 | d820d2891 |
15 | 7c4a86d83 |
hex | 4aab92c5f |
20044131423 has 4 divisors (see below), whose sum is σ = 26725508568. Its totient is φ = 13362754280.
The previous prime is 20044131409. The next prime is 20044131449. The reversal of 20044131423 is 32413144002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20044131423 - 225 = 20010576991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20044131393 and 20044131402.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20044131493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3340688568 + ... + 3340688573.
It is an arithmetic number, because the mean of its divisors is an integer number (6681377142).
Almost surely, 220044131423 is an apocalyptic number.
20044131423 is a deficient number, since it is larger than the sum of its proper divisors (6681377145).
20044131423 is an equidigital number, since it uses as much as digits as its factorization.
20044131423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6681377144.
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 20044131423 its reverse (32413144002), we get a palindrome (52457275425).
The spelling of 20044131423 in words is "twenty billion, forty-four million, one hundred thirty-one thousand, four hundred twenty-three".
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