Base | Representation |
---|---|
bin | 10010101010101110… |
… | …010010110010100101 |
3 | 1220201220120101021111 |
4 | 102222232102302211 |
5 | 312022244201433 |
6 | 13112543145021 |
7 | 1306466210101 |
oct | 225256226245 |
9 | 56656511244 |
10 | 20044131493 |
11 | 8556431731 |
12 | 3a748a5171 |
13 | 1b75889b49 |
14 | d820d2901 |
15 | 7c4a86dcd |
hex | 4aab92ca5 |
20044131493 has 2 divisors, whose sum is σ = 20044131494. Its totient is φ = 20044131492.
The previous prime is 20044131487. The next prime is 20044131509. The reversal of 20044131493 is 39413144002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 15609503844 + 4434627649 = 124938^2 + 66593^2 .
It is a cyclic number.
It is not a de Polignac number, because 20044131493 - 213 = 20044123301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20044131593) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10022065746 + 10022065747.
It is an arithmetic number, because the mean of its divisors is an integer number (10022065747).
Almost surely, 220044131493 is an apocalyptic number.
It is an amenable number.
20044131493 is a deficient number, since it is larger than the sum of its proper divisors (1).
20044131493 is an equidigital number, since it uses as much as digits as its factorization.
20044131493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 20044131493 its reverse (39413144002), we get a palindrome (59457275495).
The spelling of 20044131493 in words is "twenty billion, forty-four million, one hundred thirty-one thousand, four hundred ninety-three".
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