Base | Representation |
---|---|
bin | 11101001011010101110… |
… | …110010010111111110011 |
3 | 21002200100212021110011111 |
4 | 131023111312102333303 |
5 | 230322311342244111 |
6 | 4133034232054151 |
7 | 264600552251302 |
oct | 35132566227763 |
9 | 7080325243144 |
10 | 2005042540531 |
11 | 703374274158 |
12 | 284710834357 |
13 | 1170c8168c74 |
14 | 6d08a466439 |
15 | 37250a38a21 |
hex | 1d2d5d92ff3 |
2005042540531 has 2 divisors, whose sum is σ = 2005042540532. Its totient is φ = 2005042540530.
The previous prime is 2005042540387. The next prime is 2005042540547. The reversal of 2005042540531 is 1350452405002.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2005042540531 is a prime.
It is a super-2 number, since 2×20050425405312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2005042540493 and 2005042540502.
It is not a weakly prime, because it can be changed into another prime (2005042540591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1002521270265 + 1002521270266.
It is an arithmetic number, because the mean of its divisors is an integer number (1002521270266).
Almost surely, 22005042540531 is an apocalyptic number.
2005042540531 is a deficient number, since it is larger than the sum of its proper divisors (1).
2005042540531 is an equidigital number, since it uses as much as digits as its factorization.
2005042540531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24000, while the sum is 31.
Adding to 2005042540531 its reverse (1350452405002), we get a palindrome (3355494945533).
The spelling of 2005042540531 in words is "two trillion, five billion, forty-two million, five hundred forty thousand, five hundred thirty-one".
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