Base | Representation |
---|---|
bin | 11101001011010101110… |
… | …110010011000000101111 |
3 | 21002200100212021110020201 |
4 | 131023111312103000233 |
5 | 230322311342244331 |
6 | 4133034232054331 |
7 | 264600552251416 |
oct | 35132566230057 |
9 | 7080325243221 |
10 | 2005042540591 |
11 | 703374274202 |
12 | 2847108343a7 |
13 | 1170c8168cbc |
14 | 6d08a46647d |
15 | 37250a38a61 |
hex | 1d2d5d9302f |
2005042540591 has 2 divisors, whose sum is σ = 2005042540592. Its totient is φ = 2005042540590.
The previous prime is 2005042540583. The next prime is 2005042540597. The reversal of 2005042540591 is 1950452405002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2005042540591 - 23 = 2005042540583 is a prime.
It is a super-2 number, since 2×20050425405912 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2005042540591.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2005042540597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1002521270295 + 1002521270296.
It is an arithmetic number, because the mean of its divisors is an integer number (1002521270296).
Almost surely, 22005042540591 is an apocalyptic number.
2005042540591 is a deficient number, since it is larger than the sum of its proper divisors (1).
2005042540591 is an equidigital number, since it uses as much as digits as its factorization.
2005042540591 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 37.
Adding to 2005042540591 its reverse (1950452405002), we get a palindrome (3955494945593).
The spelling of 2005042540591 in words is "two trillion, five billion, forty-two million, five hundred forty thousand, five hundred ninety-one".
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