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2005125502577 is a prime number
BaseRepresentation
bin11101001011011010110…
…010110001011001110001
321002200120122101100200212
4131023122302301121301
5230322444112040302
64133050354153505
7264602610362201
oct35133262613161
97080518340625
102005125502577
1170340708882a
12284734582895
1311710c3c5632
146d0974a0401
1537257e75052
hex1d2dacb1671

2005125502577 has 2 divisors, whose sum is σ = 2005125502578. Its totient is φ = 2005125502576.

The previous prime is 2005125502547. The next prime is 2005125502579. The reversal of 2005125502577 is 7752055215002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1821700887616 + 183424614961 = 1349704^2 + 428281^2 .

It is a cyclic number.

It is not a de Polignac number, because 2005125502577 - 214 = 2005125486193 is a prime.

Together with 2005125502579, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (2005125502579) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1002562751288 + 1002562751289.

It is an arithmetic number, because the mean of its divisors is an integer number (1002562751289).

Almost surely, 22005125502577 is an apocalyptic number.

It is an amenable number.

2005125502577 is a deficient number, since it is larger than the sum of its proper divisors (1).

2005125502577 is an equidigital number, since it uses as much as digits as its factorization.

2005125502577 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 245000, while the sum is 41.

The spelling of 2005125502577 in words is "two trillion, five billion, one hundred twenty-five million, five hundred two thousand, five hundred seventy-seven".