Base | Representation |
---|---|
bin | 1011101011000101001… |
… | …0110110101011000101 |
3 | 201011122012001012211211 |
4 | 2322301102312223011 |
5 | 11241203002133011 |
6 | 232043404331421 |
7 | 20326433264035 |
oct | 2726122665305 |
9 | 634565035754 |
10 | 200543005381 |
11 | 78060331184 |
12 | 32a49543b71 |
13 | 15bac980a34 |
14 | 99c626d8c5 |
15 | 533ae84b21 |
hex | 2eb14b6ac5 |
200543005381 has 2 divisors, whose sum is σ = 200543005382. Its totient is φ = 200543005380.
The previous prime is 200543005237. The next prime is 200543005391. The reversal of 200543005381 is 183500345002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 171264373281 + 29278632100 = 413841^2 + 171110^2 .
It is a cyclic number.
It is not a de Polignac number, because 200543005381 - 29 = 200543004869 is a prime.
It is a super-2 number, since 2×2005430053812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200543005391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100271502690 + 100271502691.
It is an arithmetic number, because the mean of its divisors is an integer number (100271502691).
Almost surely, 2200543005381 is an apocalyptic number.
It is an amenable number.
200543005381 is a deficient number, since it is larger than the sum of its proper divisors (1).
200543005381 is an equidigital number, since it uses as much as digits as its factorization.
200543005381 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
The spelling of 200543005381 in words is "two hundred billion, five hundred forty-three million, five thousand, three hundred eighty-one".
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