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200545148149 is a prime number
BaseRepresentation
bin1011101011000101101…
…1000001110011110101
3201011122100002002011121
42322301123001303311
511241204024220044
6232043522303541
720326460430133
oct2726133016365
9634570062147
10200545148149
1178061565065
1232a4a1b7bb1
1315bb0251148
1499c666a753
15533b259984
hex2eb16c1cf5

200545148149 has 2 divisors, whose sum is σ = 200545148150. Its totient is φ = 200545148148.

The previous prime is 200545148117. The next prime is 200545148159. The reversal of 200545148149 is 941841545002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 150897287025 + 49647861124 = 388455^2 + 222818^2 .

It is a cyclic number.

It is not a de Polignac number, because 200545148149 - 25 = 200545148117 is a prime.

It is a super-2 number, since 2×2005451481492 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200545148159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100272574074 + 100272574075.

It is an arithmetic number, because the mean of its divisors is an integer number (100272574075).

Almost surely, 2200545148149 is an apocalyptic number.

It is an amenable number.

200545148149 is a deficient number, since it is larger than the sum of its proper divisors (1).

200545148149 is an equidigital number, since it uses as much as digits as its factorization.

200545148149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 230400, while the sum is 43.

The spelling of 200545148149 in words is "two hundred billion, five hundred forty-five million, one hundred forty-eight thousand, one hundred forty-nine".