Base | Representation |
---|---|
bin | 11101001111111101010… |
… | …101111101100101010111 |
3 | 21010011011100211120220111 |
4 | 131033331111331211113 |
5 | 230412440012321101 |
6 | 4135214210143451 |
7 | 265134451060222 |
oct | 35177525754527 |
9 | 7104140746814 |
10 | 2010000120151 |
11 | 7054887380a1 |
12 | 285674b81b87 |
13 | 11770829442a |
14 | 6d3daa445b9 |
15 | 37440db1251 |
hex | 1d3fd57d957 |
2010000120151 has 2 divisors, whose sum is σ = 2010000120152. Its totient is φ = 2010000120150.
The previous prime is 2010000120091. The next prime is 2010000120169. The reversal of 2010000120151 is 1510210000102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2010000120151 - 211 = 2010000118103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2010000120251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005000060075 + 1005000060076.
It is an arithmetic number, because the mean of its divisors is an integer number (1005000060076).
Almost surely, 22010000120151 is an apocalyptic number.
2010000120151 is a deficient number, since it is larger than the sum of its proper divisors (1).
2010000120151 is an equidigital number, since it uses as much as digits as its factorization.
2010000120151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20, while the sum is 13.
Adding to 2010000120151 its reverse (1510210000102), we get a palindrome (3520210120253).
The spelling of 2010000120151 in words is "two trillion, ten billion, one hundred twenty thousand, one hundred fifty-one".
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