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201010425433 is a prime number
BaseRepresentation
bin1011101100110100100…
…1111010111001011001
3201012211202120121121121
42323031021322321121
511243132132103213
6232202023005241
720344140265516
oct2731511727131
9635752517547
10201010425433
1178280165844
1232b59b99821
1315c5576974c
149a2c38430d
15536701488d
hex2ecd27ae59

201010425433 has 2 divisors, whose sum is σ = 201010425434. Its totient is φ = 201010425432.

The previous prime is 201010425389. The next prime is 201010425439. The reversal of 201010425433 is 334524010102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 200907443529 + 102981904 = 448227^2 + 10148^2 .

It is a cyclic number.

It is not a de Polignac number, because 201010425433 - 233 = 192420490841 is a prime.

It is a super-2 number, since 2×2010104254332 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 201010425398 and 201010425407.

It is not a weakly prime, because it can be changed into another prime (201010425439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100505212716 + 100505212717.

It is an arithmetic number, because the mean of its divisors is an integer number (100505212717).

Almost surely, 2201010425433 is an apocalyptic number.

It is an amenable number.

201010425433 is a deficient number, since it is larger than the sum of its proper divisors (1).

201010425433 is an equidigital number, since it uses as much as digits as its factorization.

201010425433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 201010425433 its reverse (334524010102), we get a palindrome (535534435535).

The spelling of 201010425433 in words is "two hundred one billion, ten million, four hundred twenty-five thousand, four hundred thirty-three".