Base | Representation |
---|---|
bin | 11101010000000100101… |
… | …010101101100101000011 |
3 | 21010011110221001112112212 |
4 | 131100010222231211003 |
5 | 230413212442001011 |
6 | 4135234320012335 |
7 | 265140502405001 |
oct | 35200452554503 |
9 | 7104427045485 |
10 | 2010123000131 |
11 | 7055410366a4 |
12 | 2856aa1610ab |
13 | 11772788918c |
14 | 6d40d0ada71 |
15 | 3744ba8508b |
hex | 1d404aad943 |
2010123000131 has 2 divisors, whose sum is σ = 2010123000132. Its totient is φ = 2010123000130.
The previous prime is 2010123000107. The next prime is 2010123000133. The reversal of 2010123000131 is 1310003210102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2010123000131 - 210 = 2010122999107 is a prime.
It is a super-2 number, since 2×20101230001312 (a number of 25 digits) contains 22 as substring.
Together with 2010123000133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2010123000133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005061500065 + 1005061500066.
It is an arithmetic number, because the mean of its divisors is an integer number (1005061500066).
Almost surely, 22010123000131 is an apocalyptic number.
2010123000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2010123000131 is an equidigital number, since it uses as much as digits as its factorization.
2010123000131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 2010123000131 its reverse (1310003210102), we get a palindrome (3320126210233).
The spelling of 2010123000131 in words is "two trillion, ten billion, one hundred twenty-three million, one hundred thirty-one", and thus it is an aban number.
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