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201020111212147 is a prime number
BaseRepresentation
bin101101101101001110100100…
…010100100100111001110011
3222100202100001011211220200121
4231231032210110210321303
5202322003141432242042
61551311210401031111
760225136515461233
oct5555164424447163
9870670034756617
10201020111212147
1159062172217627
121a667064625497
138822165ca0346
14378d5d5021cc3
151838edb1dd367
hexb6d3a4524e73

201020111212147 has 2 divisors, whose sum is σ = 201020111212148. Its totient is φ = 201020111212146.

The previous prime is 201020111212087. The next prime is 201020111212343. The reversal of 201020111212147 is 741212111020102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 201020111212147 - 215 = 201020111179379 is a prime.

It is a super-2 number, since 2×2010201112121472 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (201020111216147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100510055606073 + 100510055606074.

It is an arithmetic number, because the mean of its divisors is an integer number (100510055606074).

Almost surely, 2201020111212147 is an apocalyptic number.

201020111212147 is a deficient number, since it is larger than the sum of its proper divisors (1).

201020111212147 is an equidigital number, since it uses as much as digits as its factorization.

201020111212147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 448, while the sum is 25.

Adding to 201020111212147 its reverse (741212111020102), we get a palindrome (942232222232249).

The spelling of 201020111212147 in words is "two hundred one trillion, twenty billion, one hundred eleven million, two hundred twelve thousand, one hundred forty-seven".