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20103243313597 is a prime number
BaseRepresentation
bin1001001001000101001101…
…01011010011000110111101
32122011211222120222020202021
410210202212223103012331
510113332420242013342
6110431145200400141
74143261052506103
oct444424653230675
978154876866667
1020103243313597
11645081283a6a4
122308187616051
13b2a95ca18b42
144d7005d3dc73
1524cde8bc7567
hex1248a6ad31bd

20103243313597 has 2 divisors, whose sum is σ = 20103243313598. Its totient is φ = 20103243313596.

The previous prime is 20103243313453. The next prime is 20103243313631. The reversal of 20103243313597 is 79531334230102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18073840779556 + 2029402534041 = 4251334^2 + 1424571^2 .

It is a cyclic number.

It is not a de Polignac number, because 20103243313597 - 211 = 20103243311549 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20103243013597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10051621656798 + 10051621656799.

It is an arithmetic number, because the mean of its divisors is an integer number (10051621656799).

Almost surely, 220103243313597 is an apocalyptic number.

It is an amenable number.

20103243313597 is a deficient number, since it is larger than the sum of its proper divisors (1).

20103243313597 is an equidigital number, since it uses as much as digits as its factorization.

20103243313597 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 408240, while the sum is 43.

Adding to 20103243313597 its reverse (79531334230102), we get a palindrome (99634577543699).

The spelling of 20103243313597 in words is "twenty trillion, one hundred three billion, two hundred forty-three million, three hundred thirteen thousand, five hundred ninety-seven".