Base | Representation |
---|---|
bin | 1001001001000101001101… |
… | …01011010011000110111101 |
3 | 2122011211222120222020202021 |
4 | 10210202212223103012331 |
5 | 10113332420242013342 |
6 | 110431145200400141 |
7 | 4143261052506103 |
oct | 444424653230675 |
9 | 78154876866667 |
10 | 20103243313597 |
11 | 645081283a6a4 |
12 | 2308187616051 |
13 | b2a95ca18b42 |
14 | 4d7005d3dc73 |
15 | 24cde8bc7567 |
hex | 1248a6ad31bd |
20103243313597 has 2 divisors, whose sum is σ = 20103243313598. Its totient is φ = 20103243313596.
The previous prime is 20103243313453. The next prime is 20103243313631. The reversal of 20103243313597 is 79531334230102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18073840779556 + 2029402534041 = 4251334^2 + 1424571^2 .
It is a cyclic number.
It is not a de Polignac number, because 20103243313597 - 211 = 20103243311549 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20103243013597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10051621656798 + 10051621656799.
It is an arithmetic number, because the mean of its divisors is an integer number (10051621656799).
Almost surely, 220103243313597 is an apocalyptic number.
It is an amenable number.
20103243313597 is a deficient number, since it is larger than the sum of its proper divisors (1).
20103243313597 is an equidigital number, since it uses as much as digits as its factorization.
20103243313597 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 408240, while the sum is 43.
Adding to 20103243313597 its reverse (79531334230102), we get a palindrome (99634577543699).
The spelling of 20103243313597 in words is "twenty trillion, one hundred three billion, two hundred forty-three million, three hundred thirteen thousand, five hundred ninety-seven".
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