Base | Representation |
---|---|
bin | 10010101110010011… |
… | …001101100011001011 |
3 | 1220220002111011211221 |
4 | 102232103031203023 |
5 | 312133130003003 |
6 | 13122525302511 |
7 | 1311125243662 |
oct | 225623154313 |
9 | 56802434757 |
10 | 20104141003 |
11 | 8587299771 |
12 | 3a90a04a37 |
13 | 1b8513b22b |
14 | d8a073dd9 |
15 | 7c9e8c7bd |
hex | 4ae4cd8cb |
20104141003 has 2 divisors, whose sum is σ = 20104141004. Its totient is φ = 20104141002.
The previous prime is 20104140983. The next prime is 20104141081. The reversal of 20104141003 is 30014140102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20104141003 - 25 = 20104140971 is a prime.
It is not a weakly prime, because it can be changed into another prime (20104141303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10052070501 + 10052070502.
It is an arithmetic number, because the mean of its divisors is an integer number (10052070502).
Almost surely, 220104141003 is an apocalyptic number.
20104141003 is a deficient number, since it is larger than the sum of its proper divisors (1).
20104141003 is an equidigital number, since it uses as much as digits as its factorization.
20104141003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 20104141003 its reverse (30014140102), we get a palindrome (50118281105).
Subtracting 20104141003 from its reverse (30014140102), we obtain a palindrome (9909999099).
The spelling of 20104141003 in words is "twenty billion, one hundred four million, one hundred forty-one thousand, three".
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