Base | Representation |
---|---|
bin | 11101010000111001000… |
… | …000000001000001000011 |
3 | 21010020202010011112221122 |
4 | 131100321000001001003 |
5 | 230422012224000003 |
6 | 4135501402342455 |
7 | 265201323314252 |
oct | 35207100010103 |
9 | 7106663145848 |
10 | 2011001000003 |
11 | 705951701a26 |
12 | 2858b41baa2b |
13 | 11783774bc28 |
14 | 6d493940799 |
15 | 3749dbb8238 |
hex | 1d439001043 |
2011001000003 has 2 divisors, whose sum is σ = 2011001000004. Its totient is φ = 2011001000002.
The previous prime is 2011000999963. The next prime is 2011001000011. The reversal of 2011001000003 is 3000001001102.
It is an a-pointer prime, because the next prime (2011001000011) can be obtained adding 2011001000003 to its sum of digits (8).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2011001000003 - 28 = 2011000999747 is a prime.
It is not a weakly prime, because it can be changed into another prime (2011001000053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005500500001 + 1005500500002.
It is an arithmetic number, because the mean of its divisors is an integer number (1005500500002).
Almost surely, 22011001000003 is an apocalyptic number.
2011001000003 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011001000003 is an equidigital number, since it uses as much as digits as its factorization.
2011001000003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6, while the sum is 8.
Adding to 2011001000003 its reverse (3000001001102), we get a palindrome (5011002001105).
The spelling of 2011001000003 in words is "two trillion, eleven billion, one million, three", and thus it is an aban number and an uban number.
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