Search a number
-
+
2011001002141 is a prime number
BaseRepresentation
bin11101010000111001000…
…000000001100010011101
321010020202010011122212211
4131100321000001202131
5230422012224032031
64135501402400421
7265201323323425
oct35207100014235
97106663148784
102011001002141
1170595170359a
122858b4200111
1311783774cbb1
146d493941485
153749dbb8bb1
hex1d43900189d

2011001002141 has 2 divisors, whose sum is σ = 2011001002142. Its totient is φ = 2011001002140.

The previous prime is 2011001002099. The next prime is 2011001002159. The reversal of 2011001002141 is 1412001001102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1923272486041 + 87728516100 = 1386821^2 + 296190^2 .

It is a cyclic number.

It is not a de Polignac number, because 2011001002141 - 29 = 2011001001629 is a prime.

It is a super-3 number, since 3×20110010021413 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2011001092141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005500501070 + 1005500501071.

It is an arithmetic number, because the mean of its divisors is an integer number (1005500501071).

Almost surely, 22011001002141 is an apocalyptic number.

It is an amenable number.

2011001002141 is a deficient number, since it is larger than the sum of its proper divisors (1).

2011001002141 is an equidigital number, since it uses as much as digits as its factorization.

2011001002141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 2011001002141 its reverse (1412001001102), we get a palindrome (3423002003243).

The spelling of 2011001002141 in words is "two trillion, eleven billion, one million, two thousand, one hundred forty-one".