Base | Representation |
---|---|
bin | 11101010000111001000… |
… | …000000011101110010101 |
3 | 21010020202010012010011101 |
4 | 131100321000003232111 |
5 | 230422012224323333 |
6 | 4135501402510101 |
7 | 265201323361504 |
oct | 35207100035625 |
9 | 7106663163141 |
10 | 2011001011093 |
11 | 70595170a298 |
12 | 2858b4205331 |
13 | 117837753ca9 |
14 | 6d49394483b |
15 | 3749dbbb67d |
hex | 1d439003b95 |
2011001011093 has 2 divisors, whose sum is σ = 2011001011094. Its totient is φ = 2011001011092.
The previous prime is 2011001011001. The next prime is 2011001011127. The reversal of 2011001011093 is 3901101001102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1219538122929 + 791462888164 = 1104327^2 + 889642^2 .
It is a cyclic number.
It is not a de Polignac number, because 2011001011093 - 237 = 1873562057621 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2011001011093.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011001011693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005500505546 + 1005500505547.
It is an arithmetic number, because the mean of its divisors is an integer number (1005500505547).
Almost surely, 22011001011093 is an apocalyptic number.
It is an amenable number.
2011001011093 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011001011093 is an equidigital number, since it uses as much as digits as its factorization.
2011001011093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 19.
Adding to 2011001011093 its reverse (3901101001102), we get a palindrome (5912102012195).
The spelling of 2011001011093 in words is "two trillion, eleven billion, one million, eleven thousand, ninety-three".
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