Base | Representation |
---|---|
bin | 11101010000111001010… |
… | …001011000101011110111 |
3 | 21010020202102201220000221 |
4 | 131100321101120223313 |
5 | 230422014410202044 |
6 | 4135502044115211 |
7 | 265201410110413 |
oct | 35207121305367 |
9 | 7106672656027 |
10 | 2011005553399 |
11 | 705954231a67 |
12 | 2858b5835b07 |
13 | 11783868464b |
14 | 6d4943a7d43 |
15 | 3749e2b7484 |
hex | 1d439458af7 |
2011005553399 has 2 divisors, whose sum is σ = 2011005553400. Its totient is φ = 2011005553398.
The previous prime is 2011005553369. The next prime is 2011005553519. The reversal of 2011005553399 is 9933555001102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2011005553399 - 211 = 2011005551351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011005553369) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005502776699 + 1005502776700.
It is an arithmetic number, because the mean of its divisors is an integer number (1005502776700).
Almost surely, 22011005553399 is an apocalyptic number.
2011005553399 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011005553399 is an equidigital number, since it uses as much as digits as its factorization.
2011005553399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 182250, while the sum is 43.
The spelling of 2011005553399 in words is "two trillion, eleven billion, five million, five hundred fifty-three thousand, three hundred ninety-nine".
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