Base | Representation |
---|---|
bin | 1001001001010001111110… |
… | …10111111100011000100111 |
3 | 2122012111200110021011101201 |
4 | 10210220333113330120213 |
5 | 10113440441112334002 |
6 | 110434241421503331 |
7 | 4143623012430442 |
oct | 444507727743047 |
9 | 78174613234351 |
10 | 20110100121127 |
11 | 6453711281685 |
12 | 230957ba11b47 |
13 | b2b4b34675c3 |
14 | 4d7496864659 |
15 | 24d19ab59087 |
hex | 124a3f5fc627 |
20110100121127 has 2 divisors, whose sum is σ = 20110100121128. Its totient is φ = 20110100121126.
The previous prime is 20110100121119. The next prime is 20110100121149. The reversal of 20110100121127 is 72112100101102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20110100121127 - 23 = 20110100121119 is a prime.
It is a super-3 number, since 3×201101001211273 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20110100121187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055050060563 + 10055050060564.
It is an arithmetic number, because the mean of its divisors is an integer number (10055050060564).
Almost surely, 220110100121127 is an apocalyptic number.
20110100121127 is a deficient number, since it is larger than the sum of its proper divisors (1).
20110100121127 is an equidigital number, since it uses as much as digits as its factorization.
20110100121127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 20110100121127 its reverse (72112100101102), we get a palindrome (92222200222229).
The spelling of 20110100121127 in words is "twenty trillion, one hundred ten billion, one hundred million, one hundred twenty-one thousand, one hundred twenty-seven".
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