Base | Representation |
---|---|
bin | 11101010000111001100… |
… | …110111101110001001101 |
3 | 21010020202211101021212102 |
4 | 131100321212331301031 |
5 | 230422022332212232 |
6 | 4135502405244445 |
7 | 265201506151034 |
oct | 35207146756115 |
9 | 7106684337772 |
10 | 2011011210317 |
11 | 7059574460aa |
12 | 2858b7703725 |
13 | 1178398b5435 |
14 | 6d49503b71b |
15 | 3749ea33662 |
hex | 1d4399bdc4d |
2011011210317 has 2 divisors, whose sum is σ = 2011011210318. Its totient is φ = 2011011210316.
The previous prime is 2011011210289. The next prime is 2011011210347. The reversal of 2011011210317 is 7130121101102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1541486132356 + 469525077961 = 1241566^2 + 685219^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2011011210317 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011011210347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005505605158 + 1005505605159.
It is an arithmetic number, because the mean of its divisors is an integer number (1005505605159).
Almost surely, 22011011210317 is an apocalyptic number.
It is an amenable number.
2011011210317 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011011210317 is an equidigital number, since it uses as much as digits as its factorization.
2011011210317 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 20.
Adding to 2011011210317 its reverse (7130121101102), we get a palindrome (9141132311419).
The spelling of 2011011210317 in words is "two trillion, eleven billion, eleven million, two hundred ten thousand, three hundred seventeen".
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