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20110122110893 is a prime number
BaseRepresentation
bin1001001001010010000001…
…01011110100111110101101
32122012111201222122100200111
410210221000223310332231
510113441012230022033
6110434243525100021
74143623400354523
oct444510053647655
978174658570614
1020110122110893
116453722730941
122309587257611
13b2b4b7b965b9
144d749974a313
1524d19ca4e7cd
hex124a40af4fad

20110122110893 has 2 divisors, whose sum is σ = 20110122110894. Its totient is φ = 20110122110892.

The previous prime is 20110122110821. The next prime is 20110122110941. The reversal of 20110122110893 is 39801122101102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19782586808644 + 327535302249 = 4447762^2 + 572307^2 .

It is a cyclic number.

It is not a de Polignac number, because 20110122110893 - 217 = 20110121979821 is a prime.

It is a super-2 number, since 2×201101221108932 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20110122116893) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055061055446 + 10055061055447.

It is an arithmetic number, because the mean of its divisors is an integer number (10055061055447).

Almost surely, 220110122110893 is an apocalyptic number.

It is an amenable number.

20110122110893 is a deficient number, since it is larger than the sum of its proper divisors (1).

20110122110893 is an equidigital number, since it uses as much as digits as its factorization.

20110122110893 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 31.

Adding to 20110122110893 its reverse (39801122101102), we get a palindrome (59911244211995).

The spelling of 20110122110893 in words is "twenty trillion, one hundred ten billion, one hundred twenty-two million, one hundred ten thousand, eight hundred ninety-three".