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2011032013044 = 223167586001087
BaseRepresentation
bin11101010000111010110…
…110010100100011110100
321010020211021112011211210
4131100322312110203310
5230422043143404134
64135504431201420
7265202151032265
oct35207266244364
97106737464753
102011032013044
1170596816453a
12285902676270
13117840cba042
146d497ad496c
15374a17922e9
hex1d43ad948f4

2011032013044 has 12 divisors (see below), whose sum is σ = 4692408030464. Its totient is φ = 670344004344.

The previous prime is 2011032012991. The next prime is 2011032013079. The reversal of 2011032013044 is 4403102301102.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-2 number, since 2×20110320130442 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2011032013044.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83793000532 + ... + 83793000555.

Almost surely, 22011032013044 is an apocalyptic number.

It is an amenable number.

2011032013044 is an abundant number, since it is smaller than the sum of its proper divisors (2681376017420).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2011032013044 is a wasteful number, since it uses less digits than its factorization.

2011032013044 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 167586001094 (or 167586001092 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 2011032013044 its reverse (4403102301102), we get a palindrome (6414134314146).

The spelling of 2011032013044 in words is "two trillion, eleven billion, thirty-two million, thirteen thousand, forty-four".

Divisors: 1 2 3 4 6 12 167586001087 335172002174 502758003261 670344004348 1005516006522 2011032013044