Base | Representation |
---|---|
bin | 1001001001010010110011… |
… | …10010010110001101011011 |
3 | 2122012112211100002110022002 |
4 | 10210221121302112031123 |
5 | 10113442343033002032 |
6 | 110434353411351215 |
7 | 4143640003112231 |
oct | 444513162261533 |
9 | 78175740073262 |
10 | 20110543250267 |
11 | 6453919425108 |
12 | 23096842b250b |
13 | b2b5541c9ab2 |
14 | 4d74d9654951 |
15 | 24d1c49db862 |
hex | 124a59c9635b |
20110543250267 has 2 divisors, whose sum is σ = 20110543250268. Its totient is φ = 20110543250266.
The previous prime is 20110543250191. The next prime is 20110543250293. The reversal of 20110543250267 is 76205234501102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20110543250267 - 222 = 20110539055963 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20110543250267.
It is not a weakly prime, because it can be changed into another prime (20110543250297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055271625133 + 10055271625134.
It is an arithmetic number, because the mean of its divisors is an integer number (10055271625134).
Almost surely, 220110543250267 is an apocalyptic number.
20110543250267 is a deficient number, since it is larger than the sum of its proper divisors (1).
20110543250267 is an equidigital number, since it uses as much as digits as its factorization.
20110543250267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 100800, while the sum is 38.
Adding to 20110543250267 its reverse (76205234501102), we get a palindrome (96315777751369).
The spelling of 20110543250267 in words is "twenty trillion, one hundred ten billion, five hundred forty-three million, two hundred fifty thousand, two hundred sixty-seven".
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