Base | Representation |
---|---|
bin | 1001001001010011101011… |
… | …01011011110001011101111 |
3 | 2122012121000221122021022211 |
4 | 10210221311223132023233 |
5 | 10113444322332204332 |
6 | 110434512045351251 |
7 | 4143654414522226 |
oct | 444516553361357 |
9 | 78177027567284 |
10 | 20111011209967 |
11 | 6454039598167 |
12 | 2309794b68527 |
13 | b2b5ca144322 |
14 | 4d7541869cbd |
15 | 24d200b26447 |
hex | 124a75ade2ef |
20111011209967 has 2 divisors, whose sum is σ = 20111011209968. Its totient is φ = 20111011209966.
The previous prime is 20111011209917. The next prime is 20111011210013. The reversal of 20111011209967 is 76990211011102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20111011209967 - 223 = 20111002821359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20111011209917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055505604983 + 10055505604984.
It is an arithmetic number, because the mean of its divisors is an integer number (10055505604984).
Almost surely, 220111011209967 is an apocalyptic number.
20111011209967 is a deficient number, since it is larger than the sum of its proper divisors (1).
20111011209967 is an equidigital number, since it uses as much as digits as its factorization.
20111011209967 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13608, while the sum is 40.
The spelling of 20111011209967 in words is "twenty trillion, one hundred eleven billion, eleven million, two hundred nine thousand, nine hundred sixty-seven".
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