Base | Representation |
---|---|
bin | 1011101101001100011… |
… | …0100100011000100011 |
3 | 201020002201100012102101 |
4 | 2323103012210120203 |
5 | 11243333203210313 |
6 | 232215545431231 |
7 | 20346461403046 |
oct | 2732306443043 |
9 | 636081305371 |
10 | 201110210083 |
11 | 7832151a4a2 |
12 | 32b8749b517 |
13 | 15c70336213 |
14 | 9a3b71ac5d |
15 | 5370b755dd |
hex | 2ed31a4623 |
201110210083 has 2 divisors, whose sum is σ = 201110210084. Its totient is φ = 201110210082.
The previous prime is 201110210017. The next prime is 201110210087. The reversal of 201110210083 is 380012011102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201110210083 - 217 = 201110079011 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 201110210083.
It is not a weakly prime, because it can be changed into another prime (201110210087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100555105041 + 100555105042.
It is an arithmetic number, because the mean of its divisors is an integer number (100555105042).
Almost surely, 2201110210083 is an apocalyptic number.
201110210083 is a deficient number, since it is larger than the sum of its proper divisors (1).
201110210083 is an equidigital number, since it uses as much as digits as its factorization.
201110210083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 201110210083 its reverse (380012011102), we get a palindrome (581122221185).
The spelling of 201110210083 in words is "two hundred one billion, one hundred ten million, two hundred ten thousand, eighty-three".
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