Base | Representation |
---|---|
bin | 101101101110100010011111… |
… | …111100100110011000100111 |
3 | 222101001221122212020221110002 |
4 | 231232202133330212120213 |
5 | 202324442223411143421 |
6 | 1551420433141051515 |
7 | 60234510013604222 |
oct | 5556423774463047 |
9 | 871057585227402 |
10 | 201110232131111 |
11 | 59097409117946 |
12 | 1a6806159b6b9b |
13 | 882a7c8b7b8b4 |
14 | 3793b03dd85b9 |
15 | 183b512ea2b0b |
hex | b6e89ff26627 |
201110232131111 has 2 divisors, whose sum is σ = 201110232131112. Its totient is φ = 201110232131110.
The previous prime is 201110232131101. The next prime is 201110232131147. The reversal of 201110232131111 is 111131232011102.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201110232131111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201110232131101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100555116065555 + 100555116065556.
It is an arithmetic number, because the mean of its divisors is an integer number (100555116065556).
Almost surely, 2201110232131111 is an apocalyptic number.
201110232131111 is a deficient number, since it is larger than the sum of its proper divisors (1).
201110232131111 is an equidigital number, since it uses as much as digits as its factorization.
201110232131111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 20.
Adding to 201110232131111 its reverse (111131232011102), we get a palindrome (312241464142213).
The spelling of 201110232131111 in words is "two hundred one trillion, one hundred ten billion, two hundred thirty-two million, one hundred thirty-one thousand, one hundred eleven".
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