Base | Representation |
---|---|
bin | 11101010000111111100… |
… | …111011111110110001001 |
3 | 21010021000212001121102021 |
4 | 131100333213133312021 |
5 | 230422224133410233 |
6 | 4135520410004441 |
7 | 265204142026003 |
oct | 35207747376611 |
9 | 7107025047367 |
10 | 2011112013193 |
11 | 7059a9335868 |
12 | 285925416721 |
13 | 11785474a4ca |
14 | 6d4a459b373 |
15 | 374a87e5e2d |
hex | 1d43f9dfd89 |
2011112013193 has 2 divisors, whose sum is σ = 2011112013194. Its totient is φ = 2011112013192.
The previous prime is 2011112013187. The next prime is 2011112013289. The reversal of 2011112013193 is 3913102111102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1790650775104 + 220461238089 = 1338152^2 + 469533^2 .
It is a cyclic number.
It is not a de Polignac number, because 2011112013193 - 29 = 2011112012681 is a prime.
It is not a weakly prime, because it can be changed into another prime (2011112013133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005556006596 + 1005556006597.
It is an arithmetic number, because the mean of its divisors is an integer number (1005556006597).
Almost surely, 22011112013193 is an apocalyptic number.
It is an amenable number.
2011112013193 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011112013193 is an equidigital number, since it uses as much as digits as its factorization.
2011112013193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 25.
Adding to 2011112013193 its reverse (3913102111102), we get a palindrome (5924214124295).
The spelling of 2011112013193 in words is "two trillion, eleven billion, one hundred twelve million, thirteen thousand, one hundred ninety-three".
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