Base | Representation |
---|---|
bin | 11101010000111111100… |
… | …111100001110001000111 |
3 | 21010021000212002000012202 |
4 | 131100333213201301013 |
5 | 230422224134133223 |
6 | 4135520410105115 |
7 | 265204142060645 |
oct | 35207747416107 |
9 | 7107025060182 |
10 | 2011112021063 |
11 | 7059a9340772 |
12 | 28592541b19b |
13 | 117854750c72 |
14 | 6d4a45a0195 |
15 | 374a87e8428 |
hex | 1d43f9e1c47 |
2011112021063 has 2 divisors, whose sum is σ = 2011112021064. Its totient is φ = 2011112021062.
The previous prime is 2011112021059. The next prime is 2011112021099. The reversal of 2011112021063 is 3601202111102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2011112021063 - 22 = 2011112021059 is a prime.
It is a super-2 number, since 2×20111120210632 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011112021663) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005556010531 + 1005556010532.
It is an arithmetic number, because the mean of its divisors is an integer number (1005556010532).
Almost surely, 22011112021063 is an apocalyptic number.
2011112021063 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011112021063 is an equidigital number, since it uses as much as digits as its factorization.
2011112021063 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 2011112021063 its reverse (3601202111102), we get a palindrome (5612314132165).
The spelling of 2011112021063 in words is "two trillion, eleven billion, one hundred twelve million, twenty-one thousand, sixty-three".
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