Base | Representation |
---|---|
bin | 11101010001000000001… |
… | …001110100010101001001 |
3 | 21010021001110222200201002 |
4 | 131101000021310111021 |
5 | 230422233434304433 |
6 | 4135521330504345 |
7 | 265204311346514 |
oct | 35210011642511 |
9 | 7107043880632 |
10 | 2011121009993 |
11 | 705a03420237 |
12 | 2859284350b5 |
13 | 11785657a564 |
14 | 6d4a585dd7b |
15 | 374a94c19e8 |
hex | 1d440274549 |
2011121009993 has 2 divisors, whose sum is σ = 2011121009994. Its totient is φ = 2011121009992.
The previous prime is 2011121009983. The next prime is 2011121010001. The reversal of 2011121009993 is 3999001211102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2007004889344 + 4116120649 = 1416688^2 + 64157^2 .
It is a cyclic number.
It is not a de Polignac number, because 2011121009993 - 216 = 2011120944457 is a prime.
It is not a weakly prime, because it can be changed into another prime (2011121009983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005560504996 + 1005560504997.
It is an arithmetic number, because the mean of its divisors is an integer number (1005560504997).
Almost surely, 22011121009993 is an apocalyptic number.
It is an amenable number.
2011121009993 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011121009993 is an equidigital number, since it uses as much as digits as its factorization.
2011121009993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748, while the sum is 38.
The spelling of 2011121009993 in words is "two trillion, eleven billion, one hundred twenty-one million, nine thousand, nine hundred ninety-three".
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