Base | Representation |
---|---|
bin | 101101101110100100001111… |
… | …011010011011000011100101 |
3 | 222101002010111012011022010201 |
4 | 231232210033122123003211 |
5 | 202330010041132020010 |
6 | 1551421342503350501 |
7 | 60234604242235354 |
oct | 5556441732330345 |
9 | 871063435138121 |
10 | 201112102220005 |
11 | 590981887a3359 |
12 | 1a680a58152431 |
13 | 882aa3643ba82 |
14 | 3793c4051799b |
15 | 183b5c225323a |
hex | b6e90f69b0e5 |
201112102220005 has 16 divisors (see below), whose sum is σ = 242548455283200. Its totient is φ = 160080401340288.
The previous prime is 201112102219939. The next prime is 201112102220063. The reversal of 201112102220005 is 500022201211102.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 201112102220005 - 215 = 201112102187237 is a prime.
It is a super-4 number, since 4×2011121022200054 (a number of 58 digits) contains 4444 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 281410209 + ... + 282123961.
It is an arithmetic number, because the mean of its divisors is an integer number (15159278455200).
Almost surely, 2201112102220005 is an apocalyptic number.
It is an amenable number.
201112102220005 is a deficient number, since it is larger than the sum of its proper divisors (41436353063195).
201112102220005 is a wasteful number, since it uses less digits than its factorization.
201112102220005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 997140.
The product of its (nonzero) digits is 160, while the sum is 19.
Adding to 201112102220005 its reverse (500022201211102), we get a palindrome (701134303431107).
The spelling of 201112102220005 in words is "two hundred one trillion, one hundred twelve billion, one hundred two million, two hundred twenty thousand, five".
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