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20111220110 = 252011122011
BaseRepresentation
bin10010101110101110…
…001101110110001110
31220220120210211120002
4102232232031312032
5312141433020420
613123341124302
71311242356532
oct225656156616
956816724502
1020111220110
118590294373
123a93259692
131b86749457
14d8ad97bc2
157ca8da075
hex4aeb8dd8e

20111220110 has 8 divisors (see below), whose sum is σ = 36200196216. Its totient is φ = 8044488040.

The previous prime is 20111220097. The next prime is 20111220119. The reversal of 20111220110 is 1102211102.

20111220110 is digitally balanced in base 5, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×201112201102 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20111220091 and 20111220100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20111220119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1005560996 + ... + 1005561015.

It is an arithmetic number, because the mean of its divisors is an integer number (4525024527).

Almost surely, 220111220110 is an apocalyptic number.

20111220110 is a deficient number, since it is larger than the sum of its proper divisors (16088976106).

20111220110 is a wasteful number, since it uses less digits than its factorization.

20111220110 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2011122018.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 20111220110 its reverse (1102211102), we get a palindrome (21213431212).

The spelling of 20111220110 in words is "twenty billion, one hundred eleven million, two hundred twenty thousand, one hundred ten".

Divisors: 1 2 5 10 2011122011 4022244022 10055610055 20111220110