Base | Representation |
---|---|
bin | 101101101110100100100010… |
… | …000000010100001010111011 |
3 | 222101002011021221002122021021 |
4 | 231232210202000110022323 |
5 | 202330011211010040123 |
6 | 1551421433445123311 |
7 | 60234615050444335 |
oct | 5556444200241273 |
9 | 871064257078237 |
10 | 201112414143163 |
11 | 59098328880896 |
12 | 1a680b246b9537 |
13 | 882aa85c528a3 |
14 | 3793c6db12455 |
15 | 183b5de819c5d |
hex | b6e9220142bb |
201112414143163 has 2 divisors, whose sum is σ = 201112414143164. Its totient is φ = 201112414143162.
The previous prime is 201112414143127. The next prime is 201112414143247. The reversal of 201112414143163 is 361341414211102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201112414143163 - 221 = 201112412046011 is a prime.
It is a super-2 number, since 2×2011124141431632 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (201112414143103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100556207071581 + 100556207071582.
It is an arithmetic number, because the mean of its divisors is an integer number (100556207071582).
Almost surely, 2201112414143163 is an apocalyptic number.
201112414143163 is a deficient number, since it is larger than the sum of its proper divisors (1).
201112414143163 is an equidigital number, since it uses as much as digits as its factorization.
201112414143163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 34.
Adding to 201112414143163 its reverse (361341414211102), we get a palindrome (562453828354265).
The spelling of 201112414143163 in words is "two hundred one trillion, one hundred twelve billion, four hundred fourteen million, one hundred forty-three thousand, one hundred sixty-three".
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