20111465531 has 2 divisors, whose sum is σ = 20111465532. Its totient is φ = 20111465530.

The previous prime is 20111465513. The next prime is 20111465533. The reversal of 20111465531 is 13556411102.

Together with previous prime (20111465513) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20111465531 - 2³⁴ = 2931596347 is a prime.

It is a super-2 number, since 2×20111465531² (a number of 21 digits) contains 22 as substring.

Together with 20111465533, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 20111465494 and 20111465503.

It is not a weakly prime, because it can be changed into another prime (20111465533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055732765 + 10055732766.

It is an arithmetic number, because the mean of its divisors is an integer number (10055732766).

Almost surely, 2^20111465531 is an apocalyptic number.

20111465531 is a deficient number, since it is larger than the sum of its proper divisors (1).

20111465531 is an equidigital number, since it uses as much as digits as its factorization.

20111465531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3600, while the sum is 29.

Adding to 20111465531 its reverse (13556411102), we get a palindrome (33667876633).

The spelling of 20111465531 in words is "twenty billion, one hundred eleven million, four hundred sixty-five thousand, five hundred thirty-one".