Base | Representation |
---|---|
bin | 10010101110110001… |
… | …001011110001101111 |
3 | 1220220122021100201011 |
4 | 102232301023301233 |
5 | 312142132414223 |
6 | 13123405530051 |
7 | 1311252106603 |
oct | 225661136157 |
9 | 56818240634 |
10 | 20111998063 |
11 | 8590775903 |
12 | 3a93573927 |
13 | 1b8695c591 |
14 | d8b11b503 |
15 | 7ca9e080d |
hex | 4aec4bc6f |
20111998063 has 2 divisors, whose sum is σ = 20111998064. Its totient is φ = 20111998062.
The previous prime is 20111998043. The next prime is 20111998069. The reversal of 20111998063 is 36089911102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20111998063 - 225 = 20078443631 is a prime.
It is a super-2 number, since 2×201119980632 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20111998069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055999031 + 10055999032.
It is an arithmetic number, because the mean of its divisors is an integer number (10055999032).
Almost surely, 220111998063 is an apocalyptic number.
20111998063 is a deficient number, since it is larger than the sum of its proper divisors (1).
20111998063 is an equidigital number, since it uses as much as digits as its factorization.
20111998063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23328, while the sum is 40.
The spelling of 20111998063 in words is "twenty billion, one hundred eleven million, nine hundred ninety-eight thousand, sixty-three".
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