Base | Representation |
---|---|
bin | 1001001001010101100010… |
… | …10001101111111111110111 |
3 | 2122012200121122002221210121 |
4 | 10210222301101233333313 |
5 | 10114003344320201101 |
6 | 110435155204432411 |
7 | 4144021245455035 |
oct | 444526121577767 |
9 | 78180548087717 |
10 | 20112011100151 |
11 | 6454501a46493 |
12 | 2309a139a8707 |
13 | b2b729343519 |
14 | 4d75d8589555 |
15 | 24d25d7d50a1 |
hex | 124ab146fff7 |
20112011100151 has 2 divisors, whose sum is σ = 20112011100152. Its totient is φ = 20112011100150.
The previous prime is 20112011100119. The next prime is 20112011100157. The reversal of 20112011100151 is 15100111021102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20112011100151 - 25 = 20112011100119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20112011100157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10056005550075 + 10056005550076.
It is an arithmetic number, because the mean of its divisors is an integer number (10056005550076).
Almost surely, 220112011100151 is an apocalyptic number.
20112011100151 is a deficient number, since it is larger than the sum of its proper divisors (1).
20112011100151 is an equidigital number, since it uses as much as digits as its factorization.
20112011100151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20, while the sum is 16.
Adding to 20112011100151 its reverse (15100111021102), we get a palindrome (35212122121253).
The spelling of 20112011100151 in words is "twenty trillion, one hundred twelve billion, eleven million, one hundred thousand, one hundred fifty-one".
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