Base | Representation |
---|---|
bin | 1011101101001110110… |
… | …0011000100100001111 |
3 | 201020010101222211121001 |
4 | 2323103230120210033 |
5 | 11243343222420101 |
6 | 232220542121131 |
7 | 20346641561113 |
oct | 2732354304417 |
9 | 636111884531 |
10 | 201120123151 |
11 | 78327080312 |
12 | 32b8a8801a7 |
13 | 15c723c733c |
14 | 9a3cb7b743 |
15 | 5371982901 |
hex | 2ed3b1890f |
201120123151 has 2 divisors, whose sum is σ = 201120123152. Its totient is φ = 201120123150.
The previous prime is 201120123101. The next prime is 201120123167. The reversal of 201120123151 is 151321021102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201120123151 - 223 = 201111734543 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201120123101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100560061575 + 100560061576.
It is an arithmetic number, because the mean of its divisors is an integer number (100560061576).
Almost surely, 2201120123151 is an apocalyptic number.
201120123151 is a deficient number, since it is larger than the sum of its proper divisors (1).
201120123151 is an equidigital number, since it uses as much as digits as its factorization.
201120123151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 19.
Adding to 201120123151 its reverse (151321021102), we get a palindrome (352441144253).
The spelling of 201120123151 in words is "two hundred one billion, one hundred twenty million, one hundred twenty-three thousand, one hundred fifty-one".
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