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20112022110133 is a prime number
BaseRepresentation
bin1001001001010101100011…
…11011101111111110110101
32122012200122101211022122201
410210222301323233332311
510114003410130011013
6110435200240424501
74144021441162102
oct444526173577665
978180571738581
1020112022110133
116454508186448
122309a17618131
13b2b72b6c99c5
144d75d9c13aa9
1524d25e75c3dd
hex124ab1eeffb5

20112022110133 has 2 divisors, whose sum is σ = 20112022110134. Its totient is φ = 20112022110132.

The previous prime is 20112022110097. The next prime is 20112022110151. The reversal of 20112022110133 is 33101122021102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11090751557284 + 9021270552849 = 3330278^2 + 3003543^2 .

It is a cyclic number.

It is not a de Polignac number, because 20112022110133 - 229 = 20111485239221 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20112022110133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20112022110163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10056011055066 + 10056011055067.

It is an arithmetic number, because the mean of its divisors is an integer number (10056011055067).

Almost surely, 220112022110133 is an apocalyptic number.

It is an amenable number.

20112022110133 is a deficient number, since it is larger than the sum of its proper divisors (1).

20112022110133 is an equidigital number, since it uses as much as digits as its factorization.

20112022110133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 20112022110133 its reverse (33101122021102), we get a palindrome (53213144131235).

The spelling of 20112022110133 in words is "twenty trillion, one hundred twelve billion, twenty-two million, one hundred ten thousand, one hundred thirty-three".