Base | Representation |
---|---|
bin | 11101010001000101100… |
… | …001100001011001101101 |
3 | 21010021021202112020200021 |
4 | 131101011201201121231 |
5 | 230422430021004442 |
6 | 4135534310002141 |
7 | 265206454236655 |
oct | 35210541413155 |
9 | 7107252466607 |
10 | 2011211109997 |
11 | 705a4a26a751 |
12 | 285952646351 |
13 | 11786c135b7b |
14 | 6d4b37d5365 |
15 | 374b236ce67 |
hex | 1d44586166d |
2011211109997 has 2 divisors, whose sum is σ = 2011211109998. Its totient is φ = 2011211109996.
The previous prime is 2011211109983. The next prime is 2011211110021. The reversal of 2011211109997 is 7999011121102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1789350327556 + 221860782441 = 1337666^2 + 471021^2 .
It is a cyclic number.
It is not a de Polignac number, because 2011211109997 - 211 = 2011211107949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011211109907) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005605554998 + 1005605554999.
It is an arithmetic number, because the mean of its divisors is an integer number (1005605554999).
Almost surely, 22011211109997 is an apocalyptic number.
It is an amenable number.
2011211109997 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011211109997 is an equidigital number, since it uses as much as digits as its factorization.
2011211109997 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20412, while the sum is 43.
The spelling of 2011211109997 in words is "two trillion, eleven billion, two hundred eleven million, one hundred nine thousand, nine hundred ninety-seven".
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