Base | Representation |
---|---|
bin | 11101010001000110001… |
… | …011100001101010110101 |
3 | 21010021022112020200010102 |
4 | 131101012023201222311 |
5 | 230422440330334031 |
6 | 4135535342003445 |
7 | 265206646650302 |
oct | 35210613415265 |
9 | 7107275220112 |
10 | 2011222121141 |
11 | 705a55500572 |
12 | 285956276585 |
13 | 1178714bca3c |
14 | 6d4b50600a9 |
15 | 374b32e57cb |
hex | 1d4462e1ab5 |
2011222121141 has 2 divisors, whose sum is σ = 2011222121142. Its totient is φ = 2011222121140.
The previous prime is 2011222121119. The next prime is 2011222121213. The reversal of 2011222121141 is 1411212221102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1015076400100 + 996145721041 = 1007510^2 + 998071^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2011222121141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011222121341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005611060570 + 1005611060571.
It is an arithmetic number, because the mean of its divisors is an integer number (1005611060571).
Almost surely, 22011222121141 is an apocalyptic number.
It is an amenable number.
2011222121141 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011222121141 is an equidigital number, since it uses as much as digits as its factorization.
2011222121141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 128, while the sum is 20.
Adding to 2011222121141 its reverse (1411212221102), we get a palindrome (3422434342243).
The spelling of 2011222121141 in words is "two trillion, eleven billion, two hundred twenty-two million, one hundred twenty-one thousand, one hundred forty-one".
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