2011224130031 has 2 divisors, whose sum is σ = 2011224130032. Its totient is φ = 2011224130030.

The previous prime is 2011224130009. The next prime is 2011224130057. The reversal of 2011224130031 is 1300314221102.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2011224130031 is a prime.

It is a super-2 number, since 2×2011224130031² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2011224129985 and 2011224130012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2011224030031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005612065015 + 1005612065016.

It is an arithmetic number, because the mean of its divisors is an integer number (1005612065016).

Almost surely, 2^{2011224130031} is an apocalyptic number.

2011224130031 is a deficient number, since it is larger than the sum of its proper divisors (1).

2011224130031 is an equidigital number, since it uses as much as digits as its factorization.

2011224130031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 2011224130031 its reverse (1300314221102), we get a palindrome (3311538351133).

The spelling of 2011224130031 in words is "two trillion, eleven billion, two hundred twenty-four million, one hundred thirty thousand, thirty-one".